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Assume that in this question, $A = 20, B = 30, C = 50$.

They find $\$100$ and want to split by ratios such that the one with the least amount at the moment gets the most. $A$ will get the most, $B$ after that, and $C$ the least and this division will be relative to the money they currently have.

If the ratios are not inverted they come out to be $2:3:5$, But how to invert it so $C$ gets the least as he has the most at the moment.

lioness99a
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E. Afzal
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1 Answers1

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Surely it would just be

\begin{align}&\color{white}=\frac1{20}:\frac1{30}:\frac1{50}\\\\ &=\frac{300}{20}:\frac{300}{30}:\frac{300}{50}\\\\ &=15:10:6\end{align}

Therefore \begin{align}A&\text{ gets } \frac{15}{31}\times 100 \approx \$48.387\cdots\\ B&\text{ gets } \frac{10}{31}\times 100 \approx \$32.258\cdots\\ C&\text{ gets } \frac{6}{31}\times 100 \approx \$19.354\cdots\end{align}

lioness99a
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