Is $x^{log(y)}$ equal to $y^{log(x)}$? If yes then how? I read it as a general property of logarithmic functions but could not understand how is it true.
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$\log(x^{\log y}) = \log(y^{\log x}) = \log x \cdot \log y$
Now conclude, based on one-to-one nature of the log function.
Deepak
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$$x^{\log y}=y^{\log x}$$
Taking log for both sides we have
$$\log y \log x = \log x \log y$$
They are equivalent!
Crazy
- 2,125
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There is a formula: $$a=e^{\ln a}.$$
Hence: $$x^{\ln y}=e^{\ln{x^{\ln y}}}=e^{\ln y\cdot \ln x}=\left(e^{\ln y}\right)^{\ln x}=y^{\ln x}.$$
farruhota
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