Euclidea 2.6 Drop a perpendicular. The Thales theory allow one to construct a right angle at point "a" it seems. Not on the segment. My solution which got 2 stars is construct line from "a" to random point "b" on the segment. Bisect this line at "c" and draw circle from "c" to "a". You have now created a diameter which allows us to use Thales. Where the circle intersects the segment "d" is perpendicular to "a". I've seen a construction using a random point outside the segment to start which earned 3 stars but I can't remember it or refind it! Help please?
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https://www.youtube.com/watch?v=HoXANQh-HLM – Raffaele Aug 14 '17 at 20:12
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Aha, thank you. The line between the intersections of 2 circles whose centres are on a line must be at right-angles to the line. Sooooo obvious! – Tim Baxter Aug 17 '17 at 10:04
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why is it perpendicular? – user 6663629 Dec 25 '19 at 23:10