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I have a function $f(X,Y) = \sum_{i=1}^n g(x_i) + \sum_{j=1}^m h(y_j) + \sum_{i=1}^n\sum_{j=1}^mk(x_i,y_j) + c$ and the objective is to prove that $f$ is strongly convex. These are the known properties regarding to the function:

  • $g$, $h$ and $k$ are allconvex. $c$ is a constant.
  • $X = \{x_1,x_2,\dots,x_n\}$, $Y=\{y_1,y_2,\dots,y_m\}$. $n$ and $m$ are known.
  • $x_i \ge 1 \text{ for } i=1,2,\dots,n$; $y_j > 0 \text{ for }j=1,2,\dots,m$. $x_i$ and $y_j$ are both finite set.
  • $g$, $h$ and $k$ are all continuous differentiable over their domains.

A concrete example would be: $f(X,Y) = (a_1\ln x_1 + b_1x_1) + (a_2\ln x_2 + b_2x_2) + (c_1(y_1-d_1)^2) +(x_1(y_1-e_1)^2) + (x_2(y_2-e_2)^2)$.

In the function of $f$, $a, b, c, d, e$ are all constants, $X = \{x_1,x_2\}$, $Y = \{y_1\}$. $g(x) = a\ln x + bx$, $h(y) = c(y-d)^2$ and $k(x,y) = x(y-e)^2$.

Is it correct to show all $f''(X,Y) >0$ to prove this? i.e. each $\frac{\partial^2 f}{\partial x \partial x} > 0$, $\frac{\partial^2 f}{\partial y \partial y} > 0$ and $\frac{\partial^2 f}{\partial x \partial y} > 0$.

By the way, does strongly convex have any connection to Lipschitz continuity?

JYY
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  • This question is missing details. What are $X$ and $Y$ (ie, what is the domain of $f$)? – Fimpellizzeri Aug 22 '17 at 05:00
  • I'v edited the question. – JYY Aug 22 '17 at 06:50
  • When you say "prove f is strongly convex", its a little unclear what you mean. Do you mean strictly convex w.r.t. X or w.r.t. Y or both? Can you please clarify what you mean. – SpicyJalapenos Aug 22 '17 at 07:12
  • strongly (not strictly) convex w.r.t both X and Y – JYY Aug 22 '17 at 07:18
  • I still don't quite understand what is the domain of $f$. Is $X$ any finite subset of $[1,\infty)$? Is it a fixed size $n$? Right now, your suggestion of considering $f''$ doesn't make much sense -- what would it mean to differentiate with respect to a subset? – Fimpellizzeri Aug 22 '17 at 13:20
  • The question is edited, more details are added. – JYY Aug 23 '17 at 00:51

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