Question: Express $$\large27\cdot16^{11}+16^7+33\cdot16^4-16^4$$ as a hexadecimal number.
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what does $\times$ mean? or is that a $x$? – Dr. Sonnhard Graubner Aug 26 '17 at 15:33
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is this $$27\cdot 16^{11}+16^7+33\cdot 16^4-16^4$$? – Dr. Sonnhard Graubner Aug 26 '17 at 15:36
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Here's a MathJax tutorial :) – Shaun Aug 26 '17 at 15:36
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Welcome to Math StackExchange! In Math.SE, while asking questions, please tell what you tried and where you're stuck, this'll encourage others to help you, otherwise your question may be flagged and closed. – MCCCS Aug 26 '17 at 15:37
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@Dr.SonnhardGraubner yes – Katikota Aug 26 '17 at 15:38
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too late the answer is given alrady – Dr. Sonnhard Graubner Aug 26 '17 at 15:41
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$$27(16^{11})+(16^7)+33(16^4)-(16^4)$$ $$=16(16^{11})+11(16^{11})+(16^7)+33(16^4)-(16^4)$$ $$=(16^{12})+11(16^{11})+(16^7)+33(16^4)-(16^4)$$ $$=(16^{12})+11(16^{11})+(16^7)+32(16^4)$$ $$=(16^{12})+11(16^{11})+(16^7)+2(16)(16^4)$$ $$=(16^{12})+11(16^{11})+(16^7)+2(16^5)$$ $$=1B00010200000_{16}$$
Franklin Pezzuti Dyer
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