We have 4K=a+bc and 6k=b+ac, but I've tried (a+b)(a-b) or expand it directly. Neither of them works... Got trapped
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\begin{eqnarray} a^2-b^2=a(a+bc)-b(b+ac)=4aK-6bk= \cdots \ddot \smile \end{eqnarray} – Donald Splutterwit Sep 26 '17 at 19:04
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https://math.stackexchange.com/questions/2442542/if-4-mid-abc-and-6-mid-bac-prove-that-2-mid-a2-b2 – Khosrotash Sep 26 '17 at 19:05