If $R_{ref}=R_{in}$ when $V_{out}=-log(\frac{V_{in}}{V_{ref}})$
What would be the relationship between $R_{ref}$ and $R_{in}$ when $V_{out}=-3log(\frac{V_{in}}{3V_{ref}})$
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What are $R_{ref}$ and $R_{in}$ over here? – The Dead Legend Sep 29 '17 at 06:54
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$R_{in}=\frac{V_{in}}{I_1}$ and $R_{ref}=\frac{V_{ref}}{I_2}$, ($I_1=I_2$) – stuart Sep 29 '17 at 09:12
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If this is electricity then $V_{out}=-\log\left(\dfrac{V_{in}}{V_{ref}}\right)$ has the wrong dimension to be a potential difference – Henry Sep 29 '17 at 23:42