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I'm reading about Total Derivative when learning machine learning concept. I'm reading to this: enter image description here

The thing I don't know is: As my knowledge, df/dt looks like a "notation" than a variable. But in this, I see that we can multiple by both side dt. It looks like dt is acting as variable. I don't get this point. Can explain for me, why can we do this. And what does the meaning of dtwhen it stands as single variable.

Thanks

hqt
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  • As far as I know, no introductory calculus book or differential equations book has an entirely satisfactory (or correct) explanation of what $dx$ means. This point has been brought up by many. – Batman Oct 01 '17 at 19:47
  • I think it is a notation/mnemonic that is true in some limit of small differences, it seems to be described as such here: https://en.m.wikipedia.org/wiki/Differential_of_a_function . It could be that $dt$ is a (dual space) base vector for the dual space that are made of functions that map vectors to scalars, too. – Emil Oct 01 '17 at 19:51
  • @Batman thanks. I maybe really means why we can "multiple dt" by both side as dt looks like variable. I think there are some mathematical reasons behind. Just because I don't know how to express that. – hqt Oct 01 '17 at 19:52

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The definition of "differential" has the equation

$$dy = f'(x) \; dx$$

or $$dy = \frac{dy}{dx} \; dx.$$

It looks like cancellation, but it isn't really. But it does say that whenever you have

$$\frac{dy}{dx} = \mbox{crud}$$

you can multiply by $dx$ to get

$$\frac{dy}{dx} \; dx= \mbox{crud} \; dx.$$

Then you can use the equation from the definition of differential to replace $\frac{dy}{dx} \; dx$ by $dy$. So it's replacement, not cancellation.

Edit: In the definition of "differential", $dx$ and $dy$ are new variables. The equation $dy = f'(x) \; dx$ shows what the relation ship is between those variables and $x$ (and sometimes $y$, too.) If you're given a specific point $(x,y)$ on the graph of $y=f(x)$, then you can think of the origin of the $dx-dy$-plane as being on that point, with the $dx$-axis parallel to the $x-axis$ and the $dy$-axis parallel to the $y$-axis. The $dx-dy$-plane is a little traveling coordinate system that goes along the function. The equation $dy = f'(x) \; dx$ is the equation of a line through the origin of that space.

  • thanks. I understood your point about this is a replacement :D Just a little thing I haven't understood yet: dy/dx = crud. "We can multiply by dx" to get dy/dx * dx = crud * dx. The thing I don't know is: why we can multiply by dx. It make think that "dx" something likes variable too. – hqt Oct 01 '17 at 19:48
  • I added some more comments in the edit. – B. Goddard Oct 01 '17 at 20:23
  • thanks. I have read this link: https://en.m.wikipedia.org/wiki/Differential_of_a_function and understanding your point about "dx-dy" is the new origin. So in the equation dy/dx * dx = crud dx. Can I understand as it is a "cancellation" instead of "replacement" ? Because on plan Oxy, the "cancellation" is normal. – hqt Oct 02 '17 at 04:33
  • It's a problem with notation. $dy/dx$ doesn't mean division, normally. But if you take $dy$ and $dx$ to be new variables, then one could, in theory write $dy/dx$ and mean division; but nobody ever does. – B. Goddard Oct 02 '17 at 10:58
  • thanks. I understood your point :D – hqt Oct 02 '17 at 12:25