Partial answer:
The Othello piece with label $k$ gets flipped once for each factor of $k$. For instance $10$ gets flipped when every piece gets flipped (factor $1$), when every second piece gets flipped (factor $2$), when every fifth piece gets flipped (factor $5$), and when every tenth piece gets flipped (factor $10$).
So the total number of flips is $\tau(1)+\tau(2)+\cdots+\tau(90)$, where $\tau(k)$ is the divisor counting function--it returns the number of positive integer divisors (factors) of $k$. But this may be unsatisfying as it trades a sum for a sum.
There is considerable information on the sum ${\sum}_{k=1}^n \tau(k)$ on the internet. For example: http://www.maths.lancs.ac.uk/jameson/cdiv.pdf