How to prove this property of conditional expectation if $X$ and $Y$ are independent and identically distributed random variables
$E[X|X+Y]=E[Y|X+Y]$?
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sure that not some information missing? – Oct 31 '17 at 17:09
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$X$ and $Y$ are independent and identically distributed – Oct 31 '17 at 17:22
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Sorry for missing an information! – Oct 31 '17 at 17:24
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See answer here. – Gordon Oct 31 '17 at 19:24