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Can anybody help me to solve the below expression. A'B'C+A'BC+AB'C+A'BC'+AB'C=AB'+A'B+BC I'm so lost just been trying to get it for awhile only using the 10 boolean simplification rules.

Kanha
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  • What did you try? How far did you get? Where did you get stuck? Please post some of your own efforts, incomplete as they may be. – Bram28 Nov 02 '17 at 16:44
  • A'B'C+A'BC+AB'C+A'BC'+AB'C=A'B'C+A'BC+AB'C+A'BC'=B'C(A'+A)+A'B(C+C')=B'C+A'B My answer is coming like this – Kanha Nov 03 '17 at 04:58
  • Well, you did that completely correct ... that original expression is indeed equivalent to B'C+A'B ... but not to AB' + A'B +BC ... so ... are you sure you have the original expressin correct? Or the goal expression? – Bram28 Nov 03 '17 at 05:08
  • Yes the original expression is this A'B'C+A'BC+AB'C+A'BC'+AB'C=AB'+A'B+BC How to prove it? – Kanha Nov 03 '17 at 06:25
  • You can't! As I said, they are not equivalent, and what's not true you cannot prove. Sorry, but math needs to have some standards of decency. – Bram28 Nov 03 '17 at 12:50

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