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$$C=\begin{bmatrix}-1 & 1 \\4 & 2 \end{bmatrix}$$

if somebody can help me to solve this question i tried to solve it but no luck while i was trying i thought that if i got C inverse and then add it by I (identity matrix) which makes it transpose = X i do not know if thats right
it will be amazing if someone helped me

thanks

Khosrotash
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yara
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1 Answers1

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$$\quad{( X ^T-2I)^{-1}=C\\ (( X ^T-2I)^{-1})^{-1}=C^{-1}\\( X ^T-2I)=C^{-1}\\X^T-2I=C^{-1}\\X^T=2I+C^{-1}\\X=(2I+C^{-1})^T}$$

Khosrotash
  • 24,922