what is the cardinal of $\prod_{n}^{}2^n$?
I tried to create an injective function from this formula to the natural numbers and stuck.
Thanks.
Asked
Active
Viewed 29 times
0
-
Do you mean $\prod_{n=1}^{\infty} 2^{{1,2,\dots, n}}$? – Robert Z Nov 10 '17 at 08:03
-
Over what does your $n$ range? And is $2^n$ meant to be the set or the (integer) function? – Steven Stadnicki Nov 10 '17 at 08:03
-
That's because you can't. – Asaf Karagila Nov 10 '17 at 08:05
-
I've closed this as a duplicate, and while it is not word-for-word a duplicate, the answers work almost entirely out of the box to this question. So the banner's "This question already has an answer" is quite accurate. – Asaf Karagila Nov 10 '17 at 08:08