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My teacher told us it was possible to convert octal(105A) to hexadecimal: it would be equal to hex(10510).

But I though it was impossible to have a number greater than the base, and A > 8 (I think, so correct me if I'm wrong).

I know that hex(A) = decimal(10) = octal(12) but I'm really confused.

TL;DR: Is this possible to have octal(105A) = hex(10510) ?

Clement
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  • You make a mistake in hex(A) to octal conversion – the octal result is 12, not 21. – CiaPan Nov 11 '17 at 22:12
  • Thank you, I corrected my mistake! – Clement Nov 11 '17 at 22:15
  • The hex should be shorter than the octal as well because the leading digit in your octal is $8^3$ while in the hex it is $16^4,$ much greater. It is also false that octal (10510) equals hex(105A). In fact hex(105A)=octal (10132) – Ross Millikan Nov 11 '17 at 22:24
  • Thank you very much for your explanations. Makes things much clearer! – Clement Nov 11 '17 at 22:26

1 Answers1

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No, it's not possible to have such input. Octal digits are 0 through 7, A is not allowed.

CiaPan
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