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I have this summation Check the image

How did I get the RHS of answer?

2 Answers2

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Hint: if $|q|<1$ then $\displaystyle\sum_{k=0}^{\infty}aq^{k-1}=\frac{a}{1-q}.$ Obesrve that the 2nd summation starts from $m=1$, so adapt this formula.

szw1710
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For a real number $q$ with $|q|<1$ we have

$ \sum_{n=0}^{\infty}q^n=\frac{1}{1-q}$ and $ \sum_{n=1}^{\infty}q^n=\frac{q}{1-q}$.

Fred
  • 77,394