0

When you flip a fraction to remove the negative exponent, do you flip all of what's on numerator and denominator? Or do you only do that with variables

Such as:

(-7a2b3c0/3a3b4c3 )-4

Will it be written as:

(3a3b4c3/7a2b3c0)4

or

(3a3b4c3/-7a2b3c0)4

or

(3a2b3c0/7a3b4c3 )-4

or

(7a2b3c0/3a3b4c3 )-4

schoolwithschool
  • 67
  • The second one. – Botond Nov 24 '17 at 09:04
  • In that particular case, the first and second are equivalent (since the exponent is even, the minus sign dissapears). But the second expression is the correct one in all cases. – Martigan Nov 24 '17 at 09:19

1 Answers1

1

just write it out step by step:

$$\left(\frac{-7a^2b^3c^0}{3a^3b^4c^3}\right)^{-4} = \frac{1}{\left(\frac{-7a^2b^3c^0}{3a^3b^4c^3}\right)^{4}} = \frac{(3a^3b^4c^3)^4}{(-7a^2b^3c^0)^4}$$ So your second option is correct. Hope this helps.

Luapham
  • 11