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I have the question

A bullet is fired horizontally at a speed of $65$ m/s from the top of a vertical cliff overlooking the sea. The height of the cliff is $10$ m.

Calculate:

a) The time for which the bullet is in the air before it enters the sea.

b) The speed and angle to the horizontal of the bullet when it enters the sea."

Here is my attempt:

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Are these correct ? If not could you point out what I have done wrong?

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Dan
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    Looks like you were doing fine until you got to the angle calculation. – amd Dec 04 '17 at 21:34
  • I am not sure how to find the angle to the horizontal any tips ? Thanks :) – Dan Dec 04 '17 at 21:36
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    You started off correctly with $\theta = \tan^{-1}(v_y/v_x)$ but then seem to have gotten confused. Just plug in the values that you’ve already computed. – amd Dec 04 '17 at 21:37
  • But does this not give a negative angle ? Can you have negative angles ? Thanks :) – Dan Dec 04 '17 at 21:52
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    What’s wrong with that? You can interpret the negative sign to mean that it’s below the horizontal. – amd Dec 04 '17 at 22:16
  • Okay thanks I understand now :) – Dan Dec 04 '17 at 22:26

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