Let $f(x) = \sqrt x $ and an asymptotic sequence is $\ x^n$ as x goes to zero. Does there exist an asymptotic expansion for f(x)?
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I am searching for f(x) – CheersApp Dec 10 '17 at 16:22
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For $x\rightarrow 0$ ? – Peter Dec 10 '17 at 16:23
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Yes, exactly x -- > 0 – CheersApp Dec 10 '17 at 16:28