Suppose I define $G(x)=\int_0^xf(t)dt$ as the area under the function $f(t)$ of which both $0$ and $x$ are within the domain of $f$, and $x$ can take any value within the domain.
Hence we can conclude $x$ is not a constant since it can take any values and also the area under the graph changes for different values of x.
Next, define $\int_0^bg(t)dt$ as the area under $g(t)$ such that $0$ and $b$ are within the domain of $g$, and $b$ is any constant value. (i.e it can be a $5$, a $13$, $\pi$, etc.)
I know that if $b$ is $5$, $13$, $\pi$ then $\int_0^5g(t)dt$, $\int_0^{13}g(t)dt$, $\int_0^{\pi}g(t)dt$ or the areas under these specific constants are constants. However my intuition tells me that since $b$ can take any constant values, $b$ itself isn't constant. Is this argument valid? Maybe it's because of my definition that $b$ can take any constant values that made it "not a constant". I know it is more than usual even in textbooks to assume $b$ in $\int_0^bf(t)dt$ is constant. And that, the author or the writer must have meant that "I'll give you a specific value, but I won't tell you what it is."
Because of this question I'm afraid I'm on the wrong path now towards learning mathematics. I'm a senior HS student (not living in US) planning to take an engineering degree, but my curiosity about the mathematics behind it especially calculus is like that of any aspiring mathematician.