If $(M^{2n}, \omega^2)$ is a symplectic manifold, then for each tangent vector $v \in T_xM$ for some $x \in M$ we may associate a $1$-form $\omega_v^1 \in T_x^* M$ by $\omega_v^1(u) = \omega^2(u,v)$.
The map carrying a vector to it's associated $1$-form is an isomorphism. My issue is with proving this.
Showing that it is injective is simple enough by looking at the kernal. It is surjectivity that I am stuck on. I'm trying to show that given an arbitrary $1$-form on $T_x M$, there is a vector, such that the image of this vector under the map constructed above, is the form.