I have to write equation of a plane which passes through a point and its perpendicular to 2 planes , but before I start solving I was thinking if can a plane be perpendicular to two other planes , if those 2 others are not parallel to each other ( linearly dependent) ?
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Ever heard of the Cartesian coordinates in 3D? – Ivan Neretin Jan 26 '18 at 14:07
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Could you explain a bit ? – Johnny Adams Jan 26 '18 at 14:19
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Think of the planes XY, XZ, and YZ. They are all pairwise perpendicular, and no two of them are parallel. – Ivan Neretin Jan 26 '18 at 14:21
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I see I was viewing it as 2D , my bad , thank you . – Johnny Adams Jan 26 '18 at 14:28
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but if it was 2d then it would be possible , right ? – Johnny Adams Jan 26 '18 at 14:29
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Sorry, I don't follow. What would be possible? There are no planes in 2D, to begin with. – Ivan Neretin Jan 26 '18 at 14:32
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I meant to say wouldn't* be possible, isn't a sheet a 2d plane ? – Johnny Adams Jan 26 '18 at 14:38
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OK, there is *only one* plane in 2D. Surely it wouldn't be perpendicular to any other plane, because there is no other plane. – Ivan Neretin Jan 26 '18 at 14:44
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I mean a 2d plane not a 2d plane in a 2d world , because yes there would be just one 2d plane in a 2d world but there can be infinity 2d planes in a 3d world – Johnny Adams Jan 26 '18 at 15:53
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If you mean 2D planes in a 3D world, then we are back at my first comment. Yes it is possible that a plane is perpendicular to two other planes. – Ivan Neretin Jan 26 '18 at 15:58
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Yes I finally got it , thanks – Johnny Adams Jan 26 '18 at 17:52
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Yes: take two perpendicular planes, and a third plane perpendicular to their intersection.
For instance: with an orthonormal basis in $\mathbf R^3$, the $(x\text{-}y)$, $(y\text{-}z)$ and $(x\text{-}z)$ planes.
Bernard
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Indeed, take any two non-parallel planes, and take a plane perpendicular to their intersection. – John Gowers Jan 26 '18 at 17:08
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That's true, but I wanted to point the planes can be pairwise perpendicular. – Bernard Jan 26 '18 at 17:10