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i am trying to understand how system responses and impulse responses work. Given that i have a system described by the following expression:

$y(n) = 3x(n+2) + 2x(n) - 4x(n-2)$

I want to calculate the system response when the signal x(n) is:

  1. $x(n) = 2$, if $n = 0,1$
  2. $x(n) = -3$, if $n = -2$
  3. $x(n) = 0$, otherwise

Can anyone explain how to achieve it?

Thanks!

Ri-Li
  • 9,038
zorro
  • 13
  • Just replace $n=0$ in the system equation to obtain $y(0)$. Do this for all $n$ to obtain $y(n)$. – Stelios Feb 25 '18 at 14:15
  • @Stelios would you mind explaining what it means x(n) = 2, if n=0,1 then? you're saying i need to substitute n with 0, so i would get y(0) = 14x; then what would x(n) = 2 mean? This is the point i don't understand! Thanks a lot for your answer! – zorro Feb 25 '18 at 14:27
  • $y(0)=3x(0+2)+2x(0)-4x(0-2)=3x(2)+2x(0)-4x(-2)$ – Stelios Feb 25 '18 at 14:46
  • @Stelios sorry my bad i might have misinterpreted everything!!! thank you! – zorro Feb 25 '18 at 14:52

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