Let's say we have a vector $v = (x_1, ..., x_n) \in \mathbb{N}^n$ where $x_1 = x_2 = ... = x_n$. Next we choose an ordered pair of coordinates at random $(i, j)$ where $i, j \in \{1, ..., n\}$ and $i \neq j$. Finally we substitute the vector $v$ with a new vector $v' = (x_1, ..., x_i + 1, ..., x_j - 1, ..., x_n)$. Now we choose again an ordered pair of coordinates at random and substitute the vector $v'$ with a new vector doing the same we did for $v$. We continue doing this until one of the coordinates becomes zero.
What is the expected number of operations we are going to make?
I know the answer for $n = 2$ because you can model this process with a random walk. If $v = (x, x)$, then the expected number of operations is the same as the expected number of steps it will take to hit $x$ or $-x$ doing a random walk starting at zero. In this case the expected number of step starting at $y$ satisfies the recurrence relation
$$E_y = 1 + \frac{1}{2} E_{y - 1} +
\frac{1}{2} E_{y + 1}. $$
Then one can solve this linear recurrence.
I tried to do the same for the original problem but the recurrence relation is more difficult. Let $F_{(x_1, ..., x_n)}$ be the expected number of operations one can make to vector $v= (x_1, ..., x_n)$ before one of the coordinates becomes zero (in this case we allow $x_1, ..., x_n$ to be different). If I'm not wrong $F$ satisfies the following relation
$$F_{(x_1, ..., x_n)} = 1 + \sum_{i, j} \frac{1}{n (n - 1)} F_{(x_1, ..., x_n) + e_{i, j}}, $$ where the $i$-th coordiante of $e_{i, j}$ is $1$, the $j$-th is $-1$ and the rest are all zero (the sum runs through all possible operations).