You don't seem to have enough data to discern how to model your
daily sales. In particular, even though speculation based on only ten
observations is very risky, I would guess that your daily sales are not
Poisson.
One characteristic of a Poisson distribution is that
the mean and variance are numerically equal. Consequently, samples
from a Poisson distribution often have $\bar X \approx S^2,$ but
for your data the sample mean is about 30 and the sample variance
is about 8.5.$
x = c(30, 28, 27, 33, 26, 29, 27, 32, 33, 34)
mean(x); var(x)
## 29.9
## 8.544444
All ten observations lie within the interval $[26,34].$ Perhaps for the short term, the manager can plan on
inventory for about 30-34 sales, to meet demand most days without
overshooting by a huge amount. If sales are subject to fluctuations
(maybe depending on advertising or season), your short-term strategy might be
to plan for the maximum daily sales during the last two weeks but never
less than the average daily sales for the last month. [Exact details of
the best strategy would depend on balancing the cost of having to many items in stock
against the cost of having too few.]
As you accumulate more data, you
may be able to find a more useful model.
As a direct answer to your proposal to model sales by a Poisson distribution,
if that proves to be reasonable over the long term: A value from an
exact Poisson computation might be more useful than using simulation.
For example, if sales were Poisson with mean 30, then an inventory of 37
items would be enough 90% of the time:
qpois(.9, 30) # Poisson quantile function, enough 90% of days
## 37
1- ppois(37, 30) # Check: probability 37 not enough, 8.9%
## 0.08901299
[Computations from R statistical software, where ppois is a Poisson
cumulative distribution function (CDF) and qpois is it's inverse. Because
the distribution is discrete, taking only integer values, quantiles
are 'rounded up' to ensure at least the probability requested.]