Is $\exp(x-x_0) = \exp(x)\cdot \exp(-x_0)$?

Question

I try to do the integral of $\exp(x-x_0)$. However, I am not sure that if it is true that $$\exp(x-x_0) = \exp(x)\cdot\exp(-x_0)$$ I don't think it is $$\dfrac{\exp(x)}{\exp(x_0)}$$

score 0 · Accepted Answer · answered Mar 27 '18 at 03:30

0

$$\exp(x-x_0)= \exp(x)\exp(-x_0)= \frac{\exp(x)}{\exp(x_0)}$$

answered Mar 27 '18 at 03:30

Siong Thye Goh

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The user has edited the question, @SiongThyeGoh. – Shaun Mar 27 '18 at 05:24
thanks, from the edit history, seems like it is an unintentional change in the title. – Siong Thye Goh Mar 27 '18 at 05:36

Is $\exp(x-x_0) = \exp(x)\cdot \exp(-x_0)$?

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