Can someone tell me what an open surface bounded by a closed contour is please? I have difficulties to imagine something.
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How bout $D^o = \{x \in \mathbb{R}^2 : \|x\| < 1\}$? This is an open set, and the closed contour bounding it is precisely $S^1 = \{x \in \mathbb{R}^2 : \|x\| = 1\}$.
Pete Caradonna
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oh that is meant with that. Thank you! – OcK Apr 02 '18 at 18:28