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I am making a program where I need to include the progress of an entire class based on the number of lessons they have taken versus the number of lessons available. I understand that for a single student, the formula is number of lessons taken divided by the total number of lessons times 100.

How do I compute for it in a class level?

Please take note that some students might be ahead of their classmates in answering lessons.

Ash22
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1 Answers1

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You could label the progress of each student as $x_1,x_2, ..., x_n$, and the number of lessons each student has taken as $y_1,y_2, ..., y_n$ with $x_i = \frac{y_i}{total number of lessons} * 100$ for student i, and n being the number of students in the class. The average would be simply $\frac{\sum_{i=1}^n x_i}{n}$, where $\sum_{i=1}^n x_i = x_1 + x_2 + ... + x_n$

Hope this helps.

Brandon Loi
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  • Hmm sorry would you mind giving me an example? I understand the part where I need to compute for each student but I really don't understand the oter formula – Ash22 Apr 07 '18 at 03:31
  • The sigma notation is just simply a summation. It is the equivalent of taking the sum of all x values from i = 1 to n, then dividing the summation by n. – Brandon Loi Apr 07 '18 at 03:36
  • So is it like for example, I have 4 students whose x value is 0.4 each and 3 students whose x value is 0.2 each, so that's (2.2 / 7)*100 = 31.43%? – Ash22 Apr 07 '18 at 03:41
  • Yes, if you are calculating the average. – Brandon Loi Apr 07 '18 at 03:50
  • Oohh okay I get it. Thank you so much! :) – Ash22 Apr 07 '18 at 03:51