Answer:
We have to use Newton Raphson method.
$ x_1=0.75 \ \Rightarrow f(x_1) \approx 2.2 , \ \ f'(x_1)= ? $
I can not find out what is $ f'(x_1) \ $ ?
Can anyone help me?
Asked
Active
Viewed 56 times
0
-
1$f'(x_1) \approx 0$... are u sure you have to use Newton's method? – VoB Apr 22 '18 at 17:35
-
any method can be used – MAS Apr 22 '18 at 17:52
-
remember that the above graph is the graph of difference equation – MAS Apr 22 '18 at 17:58
1 Answers
1
Your really need to know the function f(x) to find its derivative. The slope of the graph at x = .75 appears to be > 0.
Phil H
- 5,579
-
-
The difference equation is a cubic with roots x = 0 and x = 2 and x = 3. x(x-2)(x-3) =? – Phil H Apr 22 '18 at 18:30