How is the property $b^{x+y} = b^x\cdot b^y$ related to the property $\log_b(xy) = \log_b(x)+\log_b(y)$?
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1By means of the fact that, when books prove the latter, they write the former, then a "thus", and finally the latter. – May 02 '18 at 07:59
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Welcome to MSE. Please use MathJax. – José Carlos Santos May 02 '18 at 08:00
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Review your definition/properties of the logarithm. You should be able to prove the relation between these statements. – May 02 '18 at 08:17