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I want to graph a 3d surface $ z=x^2-y^2 $as transparent with bold lines$ z=x^2 $ and $z=-y^2.$ How to do this?

User3910
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  • do you mean you want to graph the function some application? – The Integrator May 08 '18 at 12:35
  • This really depends on what graphing software you're using. Is it MATLAB? GeoGebra? Mathematica? Something else? – Arthur May 08 '18 at 12:41
  • @Arthur I would like to use geogebra. – User3910 May 08 '18 at 13:02
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    Bring up the 3D GeoGebra window. Type z = x^2-y^2 for the surface. Type Curve[t, 0, t^2, t, -3, 3] for z = x^2 (the first three variables are x, y, z values, the fourth is the parameter and -3 to 3 is the range of t). Type similar for your second curve. Adjust the properties of your 3 objects as required. – Paul May 08 '18 at 13:11
  • So Curve[0,t,-t^2,0, t, -3, 3] is z=-y^2: – User3910 May 09 '18 at 18:22
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    Yes - do it in GeoGebra and see! – Paul May 10 '18 at 08:13
  • @Paul https://ggbm.at/Ka6q5wUj would be nice to add a mesh grid to the surface. – User3910 May 10 '18 at 16:08
  • You will need to do two sets of curves. The first set will be "parallel" to $z = x^2$ and take the form $z = x^2-n^2$ for integer n from -4 to +4 say (note that $y$ now has value n not 0). Look at the sequence command to see how to efficiently do this. Similarly for $z = n^2 - y^2$ – Paul May 11 '18 at 08:57

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