How could I simplify this? It must give $\dfrac{9}{2}+\ln (2)$.
$$\left( \dfrac{4}{2}+6+\ln (2)\right) - \left( \dfrac{1}{2}+3+\ln (1)\right) =8+\ln (2)-\dfrac{7}{2}-\ln (1)=\dfrac{9}{2}+\ln (2)-\ln (1)$$
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4note: $\ln(1)=0$. – lulu May 19 '18 at 17:02
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You can also use the well-known identity $\ln(a)-\ln(b)=\ln(a/b)$ with $a=2$ and $b=1$, in case for some reason you do not remember that $\ln(1)=0$. – projectilemotion May 19 '18 at 17:10
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We have $$8-\frac{7}{2}+\ln(2)-\ln(1)=\frac{16-7}{2}+\ln(2)$$ since $$\ln(1)=0$$
Dr. Sonnhard Graubner
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