$F=AC'+BC'+BD'$
I know that $AC' -> (A \lnot\lor A) [ (C \lnot\lor C) \lnot\lor ( C \lnot\lor C)]$ ,and $BC' -> (B \lnot\lor B) [ (C \lnot\lor C) \lnot\lor ( C \lnot\lor C)]$ ,
$BD' -> (B \lnot\lor B) [ (D \lnot\lor D) \lnot\lor ( D \lnot\lor D)]$ , but how do I join them together