After solving using Sim Eq, obtained are $h=1$ and $k=1$, but I could not prove it as I did not get the exact radius $4$. My radius would always slightly run such as $18$ or $15$. Is there a step I miscalculated or skipped?
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6Instead of making everyone guess where you made a mistake, show your work. – amd Jun 02 '18 at 06:09
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1If you show your work here we can help you in a more effective way. – user Jun 02 '18 at 06:14
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@Sya Please recall that if the OP is solved you can evaluate to accept an answer among the given, more details here https://meta.stackexchange.com/questions/5234/how-does-accepting-an-answer-work – user Aug 03 '18 at 21:51
2 Answers
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HINT
Let consider the general equation $$(x-a)^2+(y-b)^2=16$$ and use the conditions
$(4-a)^2+(4-b)^2=16$
$(-2-a)^2+(-2-b)^2=16$
to find the center coordinates $(a,b)$.
user
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can this be solved using the matrix method for solving system of equation? – Mohammad Areeb Siddiqui Jun 02 '18 at 11:15
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1No it can’t since we obtai a quadratic equation with 2 different solutions. – user Jun 02 '18 at 11:28
