Hi I had a midterm last week, but something is bothering me about my midterm questions so I decided to come here and ask.
1)Prove that the following set is open subset of $R$ with respect to the usual metric. $(-10, \infty)$
2) Prove that for every $x \in R$, the set $\{x\}$ is a closed in $R$ with respect to the usual metric.
My approach to this questions:
- Union of open set is open too. So we need to show $(-10, \infty)$ as open sets. $(-10,-8)\cup(-9,-7)\cup(-8,-6)... $ But my assistant said that I need to show that set as a union of open balls. (Like $ \text{Bdu}(-9,1)\cup \text{Bdu}(-8,1)\cup...)$ So my answer is wrong.
-
- $R\backslash\{x\}=(-\infty,x)\cup(x,\infty)$
$(x,\infty)=(x,x+2)\cup(x+1,x+3)\cup(x+2,x+4)...$
$(-\infty,x)=(x-2,x)\cup(x-3,x-1)\cup(x-4,x-2)... $The set $R\backslash\{x\}$ is open, then $\{x\}$ is closed.
I got full marks from this question.
So I wonder, how can the second question be true if the first one is wrong? I am confused. Please excuse any mistakes, English is not my native language and I'm new here.