If Wayne considers the letter "Y" to be a vowel but Kristen does not, thinking that there are only 5 vowels, by what percent is the probability that a randomly selected letter out of the 26 letter alphabet will be a vowel greater in Wayne's opinion than in Kristen's opinion? A)$5$% ; B) $6$% ; C) $20$% ; D) $30$% ; E) $32$%
So for Wayne, the probability of a randomly selected letter being a vowel is $\frac{6}{26}$. For Kristen, it is $\frac{5}{26}$. Then clearly, the difference is $1/26$, and so I thought the percentage would be $\frac{1}{26} \cdot 100 = 3.85$%, but that's none of the answer choices. Rather, the solution says that I should do $\frac{1/26}{5/26} = 20$%, but I don't understand why $5/26$ should be in the denominator.