I had tried but not able to get the solution help please I am getting an inequality
$x$^2-2$x$+2-π <0
And unable to factories
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Do you mean $x^2-2x<\sin^{-1}(\sin 2)$? – Angina Seng Jun 08 '18 at 06:10
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@LordSharktheUnknown edit my question please I am new in this platform and don't know how to write expression perfectly – Mohit Jun 08 '18 at 06:12
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$x^{2}-2x$ < $sin^{-1}(sin(2))$ => $x^{2}-2x$ < $\pi-2$ =>$\frac{(x-1)^{2}}{\pi-1}$<1 then from the inequality we can deduce the solution as follows $1-\sqrt{\pi-1}<x<1+\sqrt{\pi-1}$
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