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I'm trying to finish some mechanics exercises here but I'm stuck with this, and as I haven't really done math in a while, I can't seem to solve it alone

I have two parametric equations:

M: $x = e^{3t} + t$

$y = e^{6t} +2e^{3t}t + t^{2}$

Basically what I need to do is remove the 't' element and be left with a standalone equation for a trajectory. Any ideas/tips?

nonuser
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Edward B
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  • By inspection $ y=x^2$ here.. but it is always not possible in $x$ to be solved for $t$ or a function of $t$ to plug it into $y$ or vice versa. – Narasimham Jun 10 '18 at 00:03

1 Answers1

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Well $$x^2 = (e^{3t}+t)^2 = e^{6t} +2e^{3t}t + t^{2}=y$$

so $y=x^2$.

nonuser
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