Not sure whether this question is correct or not! Please help. Thanks.
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2The squares already filled in don't even meet that criteria. – Badr B Jun 10 '18 at 13:05
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Yes, this is from one of the competitive Exam paper – Dinesh Potluru Jun 10 '18 at 13:07
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Presumably the question refers to unfilled in rows, columns and diagonals in which case it is not a magic square – James Arathoon Jun 10 '18 at 13:10
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1The question is flawed then. Even if we were to assume they meant $7$ instead of $3$, that would mean that the top right corner would have to be $0$, but then that diagonal would only equal $3$, not $7$. There's no solution. – Badr B Jun 10 '18 at 13:10
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2Maybe, it is meant modulo $4$, but in this case, the exercise is made up badly. – Peter Jun 10 '18 at 13:14
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modulo 4 seems to work, but only the answers must be expressed modulo 4 – James Arathoon Jun 10 '18 at 13:16
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If the upper left number was $-2$ instead of $2$, then the answer would be
\begin{array}{|r|r|r|} \hline \color{red}{-2} & 5 & 0 \\ \hline \color{red}{3} & \color{red}{1} & -1 \\ \hline \color{red}{2} & -3 & \color{red}{4} \\ \hline \end{array}
Steven Alexis Gregory
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