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I'm trying to calculate the number ofcoefficiencies of every $x^k$
in the expansion of $(x-\frac{1}{x})^{100}$ for an arbitrary $k\in\mathbb{Z}$


Now I tried the following formula:
$\binom{100}{k}$ eventhough similar to the demonstration,
Something is missing here (and/or the lack of explanation makes it harder to understand).
help?

Sebastian Hatl
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1 Answers1

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Hint: $$\left(x-\frac{1}{x}\right)^{100}=x^{100}\left(1+(-x^{-2})\right)^{100}.$$ Now try the binomial theorem on the right-hand side.

Clayton
  • 24,751