One of the tenets of economics is that in equilibrium
$$Supply=Demand$$
Both supply and demand are functions of price. So in order to find an equilibrium we need find a price that satisfy the above equation. If supply and demand equations are well-behaved (i.e., supply equation increasing in price and demand equation decreasing in price) then there is a unique equilibrium price such that demand=supply.
So in your case
$$ a-bp = c+dp$$
Solving this equation for $p$ you obtain
$$ p = \frac{a-c}{b+d} $$
Note that the price needs to be non-negative and finite, which imposes restrictions on the parameters. Assuming that $b,d>0$ so that demand and supply functions are well behaved, we have requirement that $a-c>0$.
We can now answer your question. Differentiating $p$ wrt $a$ we obtain $$\frac{\partial p}{\partial a} = \frac{1}{b+d}>0$$
Therefore, equilibrium price increases following an increase in $a$. Moreover, since equilibrium $p$ increases, the supply function implies that the equilibrium quantity will increase as well.
So answer C is correct: Both equilibrium price and equilibrium quantity will increase.