I have a series of values. Can I modify them in a consistent manner such that it's mean remain the same but standard deviation increase by 1? 1 is just arbitrary in this example
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If $\mu$ denotes the mean and $\sigma$ the standard deviation then replace value $x$ by value: $$(1+\frac1{\sigma})(x-\mu)+\mu$$
The new mean will be $\mu$ and the new standard deviation will be: $(1+\frac1{\sigma})\sigma=\sigma+1$.
drhab
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2In effect this would be adding $\frac{x-\mu}{\sigma}$ to each $x$ – Henry Jul 27 '18 at 08:18
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You can insert mean $\pm c$ which won't change the mean but will change the variance by a calculatable amount in terms of $c$ and the original population size.
Note this only works on probability distributions on finite sets.
coffeemath
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