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Recently, I am dealing with an integral $$\int^\infty_{a+bi}f(z)dz$$ where $f(z)$ is a meromorphic function on $\mathbb C$.

The $\infty$ shall be understood as the real positive infinity, and conventionally the integral is along a straight line connecting the two endpoints.

When I draw out the integral path, I got

The path is the hypotenuse of a right angled triangle with an infinitely long base and a finite height. Thus, the slope of the integral path is zero.

So, intuitively, $$\int^\infty_{a+bi}f(z)dz=\int^{\infty+bi}_{a+bi}f(z)dz$$ and the integral path can be described as $\Im(z)=b, \Re(z)\ge a$.

Is the equality (trivially) true? If yes, how can one prove it mathematically?

Szeto
  • 11,159
  • @metamorphy Okay...So I essentially think that no poles can lie within the triangle with vertices $(a,b)$ $(R,0)$ $(R,b)$ where $R\to+\infty$. Is that always true? – Szeto Jul 30 '18 at 09:36
  • @metamorphy Thank you. Can you provide a proof? – Szeto Jul 30 '18 at 10:20

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