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Could someone please point me in the right direction as to how to enter this equation into Maxima CAS so I can simplify it?

(8a^2 + b^5 + c^-2) / (2a^5 + b^2 + c^-1/2)^-1/6

Many thanks

Amanda

Amanda
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    Be much more precise with your brackets for a start - its easy to add brackets and get a completely different formula in my CAS $$( (8a)^2 + b^5 + c^{(-2 )}) / ( (2a)^5 + b^2 + c^{(-1/2) })^{(-1/6)}$$ – James Arathoon Aug 04 '18 at 09:33
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    @Amanda: In any case, what makes you think the expression can be made simpler? – quasi Aug 04 '18 at 09:52
  • Because that's what I have been asked to do for my assignment – Amanda Aug 04 '18 at 09:56

1 Answers1

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As @JamesArathoon already mentioned, your expression as it is now admits multiple interpretations. Also you seem to miss the second part of the equation. Make sure you use parenthesis as well as the multiplication sign (*). If you want to use it in maxima, I'd recommend assigning it to a variable (in this case t). Try following:

t : (8*a^2 + b^5 + c^(-2))/(2*a^5 + b^2 + c^(-1/2))^(-1/6);
print(t);

Try it online!

flawr
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