Explain the difference in the graphs of $(x – 1)^2 + (y + 3)^2 = 4$ and $(x – 1)^2 + (z + 3)^2 = 4$, both in the $(x,y,z)$-space.
Asked
Active
Viewed 49 times
1 Answers
1
$(x-1)^2+(y+3)^2=4$ is a hollow cylinder passing through the x-y plane.
$(x-1)^2+(z+3)^2=4$ is a hollow cylinder passing through the x-z plane.
This graph will express it better,
prog_SAHIL
- 2,543
- 13
- 27
-
Thank you! I graphed the equations on GeoGebra but I did not know how to explain it. – Donna Sep 03 '18 at 22:02
