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I am unsure how to go about solving this equation to find x. Any help greatly appreciated.

saulspatz
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Confused Student
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    Set $4^x = y$, then what is $16^x$ in terms of $y$? – Sarvesh Ravichandran Iyer Sep 06 '18 at 05:45
  • See https://math.stackexchange.com/questions/1356236/what-is-the-solution-to-the-equation-9x-6x-2-cdot-4x-0 https://math.stackexchange.com/questions/384090/find-all-real-numbers-x-for-which-frac8x27x12x18x-frac76 https://math.stackexchange.com/questions/1330422/how-to-solve-this-equation-for-x-left-sqrt2-sqrt3-rightx-left-sq https://math.stackexchange.com/questions/1237837/solve-left-sqrt34-sqrt15-rightx-left-sqrt34-sqrt15-right – lab bhattacharjee Sep 06 '18 at 05:50
  • It's a quadratic equation in disguise. – zahbaz Sep 06 '18 at 05:50

1 Answers1

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Let $4^x=t$, then $16^x=(4^x)^2=t^2$

So, your equation will be $$t^2-10t+16=0$$ which is a simple quadratic equation.

Solve for $t$ first and then solve for $x$ ($\because 4^x=t $)

Your IDE
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