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Can someone help me simplify tis boolean expression, I have been trying all morning with no luck. It has multiple parameters and I have no idea if I have to use De Morgan and when. The expression is:

ABC + DE + AF +ABDF + A'F

All i come up with is is this: AB(C+DF)+DE+F but then I have to design a circuit with logical gates that accept only two parameters, so I'm lost.

Thank you all for your time!

se rebbi
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1 Answers1

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\begin{equation} \begin{split} ABC + DE + AF + A'F + ABDF &= ABC + DE +(A+A')F + ABDF \\ &= ABC + DE + (1)F + ABDF \\ &= ABC + DE + F + ABDF \\ &= ABC + DE + (1 + ABD)F \\ &= ABC + DE+ F \end{split} \end{equation}

Ahmad Bazzi
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  • Hi, thank you very much for the answer but im afraid you did a mistake right there, its A'F not AF'. – se rebbi Sep 16 '18 at 07:16
  • I have edited u can check now – Ahmad Bazzi Sep 16 '18 at 10:26
  • Thank you very much for your quick responses, the problem is that the the resulting circuit has an AND gate with three parameters, and I am restricted to logical gates with only 2 parameters(that's what the excercise demands unfortunately) – se rebbi Sep 16 '18 at 12:12
  • If the answer is useful you could upvote it and mark it as correct so that others know it was useful. – Ahmad Bazzi Sep 16 '18 at 13:32