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A geometric series has second term 6 and ratio of the seventh term to the sixth term is $3$. What does this question really means? Sorry I just couldn't get this question. $t(2)=6,$ $6=ar$ from my interpretation is the question saying $t(7) : t(6) = 3$?? what does this means and how do I proceed solving for $a$ and $r$?

MRobinson
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If the ratio between the $6^{th}$ and $7^{th}$ terms is $3$, then your common ratio will be $r=3$. You can use this and the second term to find the first term ($t_2 = rt_1$).

MRobinson
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  • okayyy??? if found it quite weird because it asked to find common ratio r but given us r .Anyway thanks! – Jon Wick Sep 17 '18 at 07:46
  • @JonWick Maybe it's just checking your understanding of what is actually meant by the common ratio? – MRobinson Sep 17 '18 at 08:08