I was trying to calculate coefficients for D6 wavelet as an exercise. When I did factorization part (where you find polynomial $L(e^{i\omega})$ such that $L(e^{i\omega})L(e^{-i\omega}) = Q(cos \omega)$), I realized that this factorization is not unique. For example, I found this representation of the scaling function:
$h(x) = \sqrt 2 [c_{0}h(2x) + c_{1}h(2x-1) + c_{2}h(2x-2) + c_{3}h(2x-3) + c_{4}h(2x-4) + c_{5}h(2x-5)]$.
Where
$c_0 \approx -0.33267054$
$c_1 \approx -0.80689156$
$c_2 \approx -0.4598775$
$c_3 \approx 0.13501099$
$c_4 \approx 0.08544126$
$c_5 \approx -0.03522629$
But Wikipedia suggests another coefficients for D6 wavelet. After reading wikipedia, I understand now that one factorization is somehow better than the others:
Among the 2A−1 possible solutions of the algebraic equations for the moment and orthogonality conditions, the one is chosen whose scaling filter has extremal phase.
Can you explain "extremal phase" concept to me? I also found this page: https://www.mathworks.com/help/wavelet/gs/extremal-phase-wavelet.html
This page says this is about faster growth of "cumulative sums of the squared coefficients" which becomes 1 eventually. So why faster growth is preferred?