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The only 1-manifolds are $\mathbb R$ and $S^1$

Any manifold is homeomorphic to the disjoint sum of its connected components. Therefore, the full classification of manifolds of dimension 1 reduces to the study of connected manifolds.

Could you please give a proof (sketch) as well or link to a good reference on the subject?

  • I just edited your question slightly. You might want to click on the link after "edited" to make sure I didn't distort your meaning. :) This question has been asked at least twice before [1] [2]. I don't know if there's a full proof anywhere on this site, but there are a few different references in the comments/answers to those questions. – Micah Feb 04 '13 at 11:19
  • another question with sketch of proof https://math.stackexchange.com/questions/1866339/how-to-prove-that-there-are-only-two-kinds-of-1-dim-manifolds-without-boundary – Nikolay Jun 07 '21 at 12:35

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Any connected manifold of dimension 1 is diffeomorphic to the circle or to the line. If you can read french : Introduction aux variétés différentielles, Jacques Lafontaine.

Damien L
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Line in the case of smooth manifolds, up to homeomorphism, there are only 2 connected 1-dimensional manifolds: the circle and the real line. You can find the proof of that fact - at least in the smooth case - in Milnor's classical text "Topology from a differentiable viewpoint", which is something always worth reading, and also in many places in the internet, for example here.