In metric space the example of discrete metric space is very trivial as in discrete msp every subset is clased as well as open,now iaaue becomes in case of normed linear space.whether such a normed linear space exists or not?I am unable to find such example please help me to solve this problem.Thanks in adavce.
Asked
Active
Viewed 192 times
0
-
Not possible in a normed linear space. in $(0,1) \cup (2,3)$ (usual metric ) both these intervals are proper clopen subsets. – Kavi Rama Murthy Oct 12 '18 at 10:35
-
Is there any theorem regarding it? – Ibrahim Oct 12 '18 at 10:36
-
Any normed linear is connected: any two points can be joined by a line segment. – Kavi Rama Murthy Oct 12 '18 at 10:37
-
I have not studied connected yet ...can you elaborate how connectedness relate this fact?? – Ibrahim Oct 12 '18 at 10:40
-
read first this wiki page – Chinnapparaj R Oct 12 '18 at 10:47
2 Answers
2
Let $X$ be a normed linear space and suppose that $A$ is a non-empty proper subset of $X$ which is open and cloded. Let $B:= X \setminus A$. Then $B$ is a non-empty proper subset of $X$ which is also open and closed. Furthermore we have
$(*) \quad X= A \cup B$.
Now take $a \in A$ and $b \in B$ and let $x(t):=a+t(b-a)$ for $t \in [0,1]$. Then $x(t) \in X$ for all $t \in [0,1]$.
It is your turn to get a contradiction to $(*)$.
Fred
- 77,394
-
Can you explain a little more.....I tried my best but didn't reach the destination.... – Ibrahim Oct 12 '18 at 11:21
0
You need any disconnected metric space! Also note that normed linear spaces are connected, so we cannot find such a set in a normed linear spaces!
For example, In $\Bbb{Q}$ with the usual metric, the set $(-\sqrt{2},\sqrt{2}) \cap \Bbb{Q}$ is clopen
Chinnapparaj R
- 11,589